A set of chemistry exam scores are normally distributed with a mean of 70 points and a standard deviation
of 5 points.
What proportion of exam scores are between 68 and 73 points?
You may round your answer to four decimal places.
please help

38.117%

Step-by-step explanation:

Firstly, what you do is to calculate the z-score of both points

Mathematically;

z-score = (x-mean)/SD

where mean = 70 and SD = 5

For 68, z-score = (68-70)/5 = -2/5 = -0.4

for 73, z-score = (73-70)/5 = 3/5 = 0.6

The probability we are to calculate ranges from

P(-0.4<z<0.6) = P(z<0.6) - P(z<-0.4)

it is at this point that we make use of z score table

= 0.38117 which is 38.117%

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

correct choice is a

step-by-step explanation:

the equation of the line passing through the points and is

thus, the equation of the line that passes through the points (0, -6) and (-3, 0) is