Question 1
The sum of the first ten terms of an Arithmetic
Progression (A. P.) is 130. If the fifth term is 3
times the first term, find the:
a. common difference;
b. first term;
c. number of terms of the A. P. if the last term is
28.

  a. 2

  b. 4

  c. 13

Step-by-step explanation:

The general term of an arithmetic progression is ...

  an = a1+d(n-1)

where a1 is the first term, and d is the common difference.

The sum of n terms is ...

  Sn = n(2a1 +d(n -1))/2

__

The given relations tell us ...

  S10 = 10(2a1 +9d)/2 = 10a1 +45d = 130

and

  a5 = 3a1

  a1 +4d = 3a1

  4d = 2a1

  2d = a1

Using this in the equation for S10 above, we have ...

  10(2d) +45d = 130

  d = 130/65 = 2

___

(a) The common difference is 2.

  d = 2

__

(b) The first term is a1 = 2d = 2(2)

  a1 = 4.

__

(c) an = 28 = 4 +2(n -1)

  24 = 2(n -1)

  12 = n -1

  13 = n

The 13th term is 28.

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

ghjmutmum

step-by-step explanation: