An expression is shown below.
f(x) = 2x2 - X - 10
Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points)
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)

Step-by-step explanation:

f(x)=2x²-x-10

B.

it is upward parabola.

so vertex is minimum.

f(x)=2(x²-1/2x+(-1/4)²-(-1/4)²)-10

=2(x-1/4)²-2/16-10

=2(x-1/4)²-1/8-10

=2(x-1/4)²-81/8

vertex is (1/4,-81/8)

C.

when x=0,f(x)=-10

when f(x)=0,2x²-x-10=0

2x²-5x+4x-10=0

x(2x-5)+2(2x-5)=0

(2x-5)(x+2)=0

x=-2,5/2

it cuts x-axis at (-2,0) and (5/2,0)

and vertex is (1/4,-81/8)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

x + 4/7

step-by-step explanation:

use cymath