When a number is decreased by 7% the result is 66. What is the original number to the nearest tenth?

61.7

Step-by-step explanation:

Let the number be x

% increase in the number : 7

Thus , actual increase in number will be 7% of x = 7/100 of x = 7x/100

Thus, new number with 7% increase = x+ 7x/100

given that value of new number with 7% increase is 66

Thus,

x+ 7x/100 = 66

=> (100x+7x)/100 = 66

=> 107 x = 66*100

=> x = 6600/107 = 61.682

Thus, original number is 61.682

but we have to find the number to nearest tenth .

original number is 61.7

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

answer: 8

step-by-step explanation: