Mathematics, 28.05.2020 22:58 davestrider404
A disease has hit a city. The percentage of the population infected t days after the disease arrives is approximated by p(t)equals8 t e Superscript negative t divided by 11 for 0less than or equalstless than or equals44. After how many days is the percentage of infected people a maximum? What is the maximum percent of the population infected?
A. The percentage of infected people reaches a maximum after__ days.
B. The maximum percent of the population infected is __%.
Answers: 2
![p '(t) = e^{-t/11}(8 -8t/11) now, p '(t) = 0 == [tex]e^{-t/11}(8-8t/11) = 0 ==8 -8t/11 = 0 == t = 88/8 = 11 days Hence percentage of infected people reaches maximum after 11 days maximum percent of the population infected = p(11) == [tex]p(11) = 8(11)e^{-11/11} ](/tpl/images/0669/3052/d44f1.png)
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A disease has hit a city. The percentage of the population infected t days after the disease arrives...
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