Write the quadratic In standard form

Can someone please help me answer this I don’t understand it

-(x^2-2x+4)=0

Step-by-step explanation:

Standard form: ax^2+bx+c=0

Add 5 to both sides: 2x^2=2x+x^2-4

Subtract 2x^2 from both sides: 0=2x-x^2-4

Switch sides: 2x-x^2-4=0

Arrange the left side into standard form: -x^2+2x-4=0

Since there's a negative for the x^2, factor it out: -(x^2-2x+4)=0

I hope this helped! Have a good rest of your day!

x^2+7x-1=0

Step-by-step explanation:

Standard Form:

y=ax^2+bx+c

-5+2x^2= -7x+x^2-4

Add four and Add 7x to both sides

-1+2x^2+7x

Subtract x^2

x^2+7x-1= 0

the diameter is 16 cm. are you a teacher?

step-by-step explanation:

if you need just tell me and i will come to the rescue.

step-by-step explanation: