PLZ help

Alice, Bob, and Carrie can all choose a number from 1 to 10 (inclusive)
Find the number of ways they can choose their numbers, if all three numbers are
different.

720 ways

Step-by-step explanation:

We have a total of 10 numbers and 3 selections:

When Alice chooses, she has 10 possible numbers to choose.

When Bob chooses, he has 9 possible numbers to choose (because one has already ben selected)

When Carrie chooses, she has 8 possible numbers to choose (because two numbers had already been selected)

The number of combinations is equal to the product of the number of options for each selection:

C = 10*9*8 = 90*8 = 720

step-by-step explanation:

which of the following statements correctly describes the expression below based on its degree and number of terms?

314 - 7x2 + 11

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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