A series consists of some numbers such that the summation of the divisors of any number of that series is 1 less than twice of that number. For example, the divisors of 4 are 1,2 and 4 and the sum is 7. If the numbers of this sequence are arranged in ascending order then what is the 9th term?

The 9th term of the series is 256

Step-by-step explanation:

Here we have the numbers as follows

1, 2, 4 from we have;

1 = The first term of the series

2 = The second term of the series

4 = The third term of the series

From the definition of the series, the sum of the factors is 1 less than twice the number, therefore, since 4 satisfies all the conditions, we observe that;

4×2×1 = 8 also satisfies all the conditions, hence we have;

8 = The fourth term of the series

8 × 2 = 16 = The fifth term of the series

16 × 2 = 32 = The sixth term of the series

32 × 2 = 64 = The seventh term of the series

64 × 2 = 128 = The eight term of the series

Therefore, the 9th term of the series = 128 × 2 = 256.

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.