The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.

The null hypothesis was failed to be rejected.

Step-by-step explanation:

The complete question is:

The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. The summary statistics are n=93, x overbar=3.92, s=0.51.

Solution:

The hypothesis is:

H₀: The smartphone carrier's mean data speed at airports is not less than 4.00 Mbps, i.e. μ ≥ 4.00.

Hₐ: The smartphone carrier's mean data speed at airports is less than 4.00 Mbps, i.e. μ < 4.00.

Compute the test statistic as follows:

Compute the p-value as follows:

*Use a t-table.

*If the desired degrees of freedom is not provided use the next higher value.

The p-value = 0.066 > α = 0.05

The null hypothesis was failed to be rejected.

Thus, it can be concluded that the smartphone carrier's mean data speed at airports is not less than 4.00 Mbps.

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh