Can someone help me?

The upper quartile is 6.

Step-by-step explanation:

FIrst, I found the median of the data, which is 4. Then, I determined the median of the upper half of the data, which is 6. The median of the upper half of the data is known as the upper quartile.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

2

step-by-step explanation: