Two six sided dice are rolled. What is the probability of one of the dice being a 4?

11/36

Step-by-step explanation:

We know there are 36 possibilities when we roll 2 die

Counting up the rolls with either 1 or 2 4's

P(one of the die being a 4) = 11/ 36

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

it would open into a square depending on the type of envelope i’m not sure about the second part