Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters

You can solve this by finding all of the factors of 28 and seeing which ones add up to 22 when doubled.

The factors of 28 are as follows:

28 x 1      28(2) + 1(2) = 56 + 2 = 58 ≠ 22
14 x 2      14(2) + 2(2) = 28 + 4 = 32 ≠ 22
 7 x 4         7(2) + 4(2) = 14 + 8 = 22

The dimensions of the rectangle are 4 x 7.

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