2x-y=10
Y=-x-1
Solve the system of equations

 (9,8)

Step-by-step explanation:

  let 2x - y = 10  be [a]   &   y = x − 1 be [b]

First, lets substitute [b] into [a] and solve for x

  2x - ( x - 1) = 10

         2x - x  = 10 - 1

                  x = 9

Now, since x = 9, we can substitute for x in [b]

      ⇒  y = 9 - 1

            y = 8

∴ the solution for the system of equations is x = 9, y = 8 OR  (9, 8)

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

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step-by-step explanation: