The equations 2 x minus 5 y = negative 5, 11 x minus 5 y = 15, 9 x + 5 y = 5, and 14 x + 5 y = negative 5 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (2, 1.5) and (0.5, negative 2). Blue line goes through (0, 1) and (0.5, 0). Pink line goes through (negative 1, 2), and (0, negative 1). Orange line goes through (0, 1) and (2, 1.75). Which system of equations has a solution of approximately (–0.6, 0.8)? 2 x minus 5 y = negative 5 and 14 x + 5 y = negative 5 2 x minus 5 y = negative 5 and 11 x minus 5 y = 15 11 x minus 5 y = 15 and 14 x + 5 y = negative 5 11 x minus 5 y = 15 and 9 x + 5 y = 5

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

c. 6tan80

step-by-step explanation: