Q8:
Maria had a package of crackers.

After she ate 8
of the crackers, there were 14
crackers left in the package.

Which equation can be used to find the number of crackers that were in the package before Maria ate the crackers?

The number of crackers that were in the package before Maria ate some, is 22 crackers.

The equation can be written as:

C=L+E

where

C: original number of crackers.

L: number of crackers left in the package.

E: number of crackers eaten.

Step-by-step explanation:

We can define C as the total crackers that were in the package.

The amount left is L and the amount she has eaten is E.

The amount of crackers left are equal to the original number of crackers less the ones she ate:

The number of crackers that were in the package before Maria ate some, is 22 crackers.

The equation can be written as:

C=L+E

where

C: original number of crackers.

L: number of crackers left in the package.

E: number of crackers eaten.

squares, rhombus, rectangles

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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