What is the angle of elevation ∅ that is required for a hit ball to just clear the center field fence when it is hit 2 ft above the ground? Show all of your work and round your answer to the nearest hundredth of a degree.

0.81°

Question:

What is the angle of elevation θ that is required for a hit ball to just clear the center field fence when it is hit 2 ft above the ground? Show all of your work and round your answer to the nearest hundredth of a degree.

Distance from Home plate to the center field fence: 425 ft

Height of the center field fence: 8 ft

Step-by-step explanation:

Find attached the diagram used for solving the problem.

The fence height = 8ft

The fence height takes 2 ft from the ground and doesn't count towards the angle.

Therefore subtract the difference = 8-2 = 6ft

The fence height from the 2ft to the fence top = 6ft

Angle of elevation (θ):

Tan(θ) = opposite/adjacent

Adjacent = Distance from Home plate to the center field fence = 425 ft

Opposite = 6ft

Tan(θ) = 6/425

Tan(θ) = 0.0141

θ = arctan(0.0141)

arctan = inverse of tangent = tan^-1

θ = 0.8078°

Angle of elevation (θ) = 0.81°

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

b

step-by-step explanation:

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