What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

Using the standard form of the equation:

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

where;

is the slope

From above;

(h,k) = 11, 100

= 100

a =

a = 10

b =

b = 2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

to be  the slope in the equation  

 =

 = 5

Thus, the  positive slope of the asymptote = 5

answer: i think you should do the math and pay attention in class : )

step-by-step explanation:

that is truly what   think but if i get the answer i will

5x10^11 x 65

325 x 10^11

or

325,