If f(x) = 2x, then f ''(x) =

f''(x) = 0

Step-by-step explanation:

f ''(x) is second derivative of f(x)

derivative of x ^n = n x^(n-1)

derivative of constant = 0

so f''(x) is derivative of derivative

f'(x) =2 * 1 * x^(1-1) =2

f''(x) = 0

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

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step-by-step explanation: