Eh man, points you want? I have points, yes!

(x+1) (x-2) (x-4)

Step-by-step explanation:

x^3-5x^2 + 2x +8

Using the rational root theorem

possible roots

±8, ±4,±2,±1

Checking 1

1-5+2+8 = 6  not a root

Checking -1

-1 -5 -2 +8 = 0

Negative 1 is a root  so we have (x+1)

Using synthetic division

    1   -5   2   8

-1       -1     6  -8

    1     -6   8   0

The remaining polynomial

x^2 -6x +8

This factor to

(x-4)(x-2)

Bringing back the (x+1)

The polynomial is

(x+1) (x-2) (x-4)

we need the options

step-by-step explanation:

you can't solve x because it is 2 linear equation and you only have one equation