Last year Oscar bought a packet of biscuits every week and found 30 of 3 these packets contained broken biscuits. What is the relative frequency
of this event? Answer correct to 2 decimal places. Explain why you
chose the numbers in your calculation

Relative Frequency = 0.58

Step-by-step explanation:

Given

A packet of biscuit every week

Number of packets that contains broken biscuits = 30

Required

Relative Frequency

First, the total packet of biscuit bought needs to be calculated.

The question says Oscar bought a packet every week of the year and there are 52 weeks in a year.

This means that Oscar bought 52 packets of biscuits.

So, we can conclude that 30 out 52 packets contains broken biscuits.

The relative frequency is then calculated as this;

Relative Frequency = Number of packets that contains broken biscuits divided by total number of packets.

Relative Frequency = 30/52

Relative Frequency = 0.5769230769

Relative Frequency = 0.58 (Approximated).

Hence, the relative frequency of the broken packets of biscuits is 0.58

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363