Lukas wants to create a triangle with sides measuring 9 in 13 in and 15 in he says that more than one triangle is possible given these side lengths which statement about Lukas claim is true

Lukas is incorrect. The side lengths do not satisfy the triangle inequality rule so no triangles can be drawn given these side lengths.

Step-by-step explanation:

Here is the complete question

Lukas wants to create a triangle with sides measuring 9 in., 13 in., and 15 in. He says that more than one triangle is possible given these side lengths. Which statement about Lukas’s claim is true?

A. Lukas is incorrect. The side lengths satisfy the triangle inequality rule so one unique triangle can be drawn.

B. Lukas is incorrect. The side lengths do not satisfy the triangle inequality rule so no triangles can be drawn given these side lengths.

C. Lukas is correct. The side lengths satisfy the triangle inequality rule so multiple triangles can be drawn.

D. Lukas is correct. The side lengths do not satisfy the triangle inequality rule so multiple triangles can be drawn.

For the figures to make up a triangle, the addition of the square of the two smaller sides must be equal to the square of the larger side. The Pythagoras rule is used.

The figures here are 9, 13 and 15. So let's yes to confirm.

9^2 + 13^2 = 15^2

81 + 169 = 225

250 = 225

Since the two figures are not equal, it is incorrect no triangles can be drawn from the length.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3