What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4 = {(x-6) and passes through the point (-2, -2)?
y=-x-10
y=-3x+10
y=x-1
y=x+1
o

what is the answer to this

and?

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )