A small fruit basket with 6 apples and 6 oranges costs $7.50. A different fruit basket with 10 apples and 5 oranges costs $8.75. If x is the cost of one apple and y is the cost of one orange, the system of equations below can be used to determine the cost of one apple and one orange.
6x+6y=7.50
10x+5y=8.75
What is the cost of one apple?
0.25
0.5
0.75
1.00

The cost of one apple given the system of equation is $0.5

Given:

6x + 6y = 7.50

10x + 5y = 8.75

multiply (1) by 5 and (2) by 6

30x + 30y = 37.5 (3)

60x + 30y = 52.5 (4)

subtract (3) from (4)

60x - 30x = 52.5 - 37.5

30x = 15

x = 15/30

x = $0.5

Substitute x = $0.5 into (1)

6x + 6y = 7.50

6(0.5) + 6y = 7.50

3 + 6y = 7.50

6y = 7.50 - 3

6y = 4.50

y = 4.50 / 6

y = $0.75

Therefore, the cost of apple and orange is $0.5 and $0.75 respectively

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The cost of one apple is  $0.5 or 50 cent.

Step-by-step explanation:

-5(6x + 6y)= 7.50(-5)

3(10x + 5y)=8.75(3)

-30x -30y = -37.5

30x  + 15y= 26.25

        -15y= -11.25

  y= 0.75

30x + 15(0.75)= 26.25

30x + 15(0.75)= 26.25

30x + 11.25= 26.25  

       -11.25     -11.25

30x= 15

x= 0.5  

i'm pretty sure it's c. nvm

your answer is the frist one

hop i