\begin{aligned} &f(t)=\dfrac{2t+7}{t-3} &h(n)=-2n^2-3n+1 \end{aligned} f(t)= t−3 2t+7 h(n)=−2n 2 −3n+1 f(h(-1))=f(h(−1))=

Step-by-step explanation:

Given:

We want to determine the value of

First, we evaluate h(-1)

Therefore:

Therefore: f(h(-1))=-11

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

step-by-step explanation: