An object is thrown off a platform that is 15 ft high with an initial velocity of 8.5 ft/is what function models the height h of the object after t seconds

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

Step-by-step explanation:

Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:

H(t) = H(0) + V(0)*t + 0.5*g*t²

Applying the data from the problem, we have:

H(t) = 15 + 8.5*t + 0.5*32.17405*t²

H(t) = 15 + 8.5*t + 16.09*t²

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

a

step-by-step explanation:

the answer is a