In triangle PQR the measure of angle R=90, QP=73, RQ=55, and PR=48. what is the value of the sine of angle P to the nearest Hundredth

P ≈ 48.89°(nearest hundredth)

Step-by-step explanation:

The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.

Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.

opposite side(QR) = 55

adjacent side(PR) = 48

hypotenuse(PQ) = 73

sin P = opposite/hypotenuse

sin P = 55/73

P = sin⁻¹ 55/73

P = sin⁻¹ 0.75342465753

P = 48.8879095605

P ≈ 48.89°(nearest hundredth)

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

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