A hemispherical bowl has a radius of 3.5 cm. What would be the
volume of water it would contain?

89.80 cm cubed

Step-by-step explanation:

A hemisphere is essentially just half of a sphere. We want to find its volume.

The volume of a sphere is denoted by: V = (4/3)π * r³, where r is the radius. That means the volume of a hemisphere, which is half a sphere, will be denoted by: V = (1/2) * (4/3)π * r³ = (2/3)π * r³.

Here, the radius is 3.5, so plug this in:

V = (2/3)π * r³

V = (2/3)π * (3.5)³ ≈ 89.80 cm cubed

89.78 cm^3

Step-by-step explanation:

The volume of a hemisphere is half of the volume of a sphere.

The volume of a sphere:

4/3 π r^3

Multiply by 1/2

1/2(4/3 π r^3 )

2/3 π r^3  

Volume of a hemisphere: 2/3 π r^3  

The radius is 3.5 centimetres. Substitute 3.5 in for r.

v=2/3 π r^3  

v=2/3 π 3.5^3  

Evaluate the exponent

v=2/3 *π *42.875

Multiply all the numbers together

v=89.7971900151

The volume of water it would contain is about 89.78 cm^3

it could be a ..idk tho

3x^3-x^2+6x-9