How much thermal energy must be removed from 3.75 kg of water to freeze it
at its melting point? Use Q = mass x latent heat of fusion

D.1,250kj

Step-by-step explanation:

Hi, to answer this question we simply have to substitute mass= 3.75 and latent heat of fusion = 333 kj/kg in the equation given:

Q = mass x latent heat of fusion

Q = 3.75 kg x 333 kj/kg

Solving:

Q = 1,248 kj = 1,250kj (rounded)

The correct option is D.1, 250kj

Feel free to ask for more if needed or if you did not understand something.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

y=x+9

?

step-by-step explanation: