What are the values of a, b and c in the quadratic equation -2x2+4x -3=0

a = - 2, b = 4, c = - 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax² + bx + c = 0 ( a ≠ 0 )

Compare  - 2x² + 4x - 3 = 0 to the standard, giving

a = - 2, b = 4, c = - 3

See below in bold.

Step-by-step explanation:

-2x^2 + 4x  - 3 = 0     Compare this with the standard form:

ax^2  + bx + c = 0

We see that a = -2, b = 4 and c = -3.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes