WILL GIVE BRAINLIEST The kilopascal is a unit of measure for atmospheric pressure. Suppose the atmospheric air pressure at sea level is about 101 kilopascals. For every 1000-m increase in altitude, the pressure decreases about 11.9%. What is the approximate pressure at an altitude of 2000 m?

The formula to calculate pressure at an altitude in this case is:

P = original pressure x (1 + rate of change)^(number of changing)

in which,

original pressure = 101 kilopascals

rate of change = -11.9% = - 0.119

number of changing = 2000/1000 = 2

=> P = 101 x (1 - 0.119)^2 = 78.39 kilopascals

Hope this helps!

:)

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.