Suppose there are two types of tickets to a show advance and same day. Advance tickets cost $25 and same dayt costs $15 for one performamnce there were 50 tickets sold in all the total amount paid for them was $1050 how many tickets of each type were sold

Advanced tickets=30 Day =20

Step-by-step explanation:

Put them into equations:

x=advanced

y=day

x+y=50

25x+15y=1050

to make it simpler re-arrange x+y=50

x=50-y

Then substitute into 25x+15y=1050

25(50-y)+15y=1050

Expand

1250-25y+15y=1050

Rearrange

25y-15y=1250-1050

Work the above out

10y=200

y=20

and then

20+x=50

meaning

x=30

showing Advanced tickets=30 Day =20

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: