A company manufactures cans of cheese designed a can that has a
radius of 2 inches and a volume of 150 cubic inches. For a new can
design, the company plans to keep the height the same and triple the
radius (it's a really wide can of cheese). What will be the effect on the
can's volume?

Correct option: second one

(Volume will be 9 times higher)

Step-by-step explanation:

The volume of a cylindrical can is given by the formula:

V = pi * r^2 * h

Where r is the base radius and h is the height.

If the new radius will be the triple of the old radius and the height will be the same, we have:

r' = 3r

h' = h

So, we can find the new volume V':

V' = pi * r'^2 * h'

V' = pi * (3r)^2 * h

V' = pi * 9r^2 * h = 9 * (pi * r^2 * h) = 9V

So we have that the new volume will be 9 times higher than the old volume.

Correct option: second one.

the correct answer is 828.07