Colton has a stone paperweight composed of a triangular pyramid on top of a triangular prism with the dimensions shown below. Use the drop-down menus to explain how to determine the volume of the paperweight. Need major help please

The complete statements are:

Start by calculating the area of the base of the pyramid using:

So, we have:

The volume of the triangular prism is then calculated using:

--- i.e. the product of area and height (4)

So, we have:

The volume of the triangular pyramid is then calculated using:

--- i.e. the product of 1/3 of the area and height (7)

So, we have:

The total volume of the shape is then as:

Hence, the volume of the paperweight is approximately 79.17 cubic inches

Read more about volume at:

link

The area of the base would be found using the area of a triangle formula which is 1/2 x base x height.

The base and height are the two sides perpendicular to each other, which are both 5 inches.

The area of the base = 1/2 x 5 x 5 = 12.5 square inches.

The volume of the triangular prism is the area of the base times the height, which is 4 inches.

Volume of the triangular prism is 12.5 x 4 = 50 cubic inches.

Volume of the triangular prism is 1/3 x area of base x height, which is 7:

Volume of the triangular prism = 1/3 x 12.5 x 7 = 29.17 cubic inches.

Total volume = 29.17 + 50 = 79.17 cubic inches.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents