An object is launched from a platform. Its height (in meters), x xx seconds after the launch, is modeled by: h ( x ) = − 5 ( x − 4 ) 2 + 180 h(x)=−5(x−4) 2 +180h, left parenthesis, x, right parenthesis, equals, minus, 5, left parenthesis, x, minus, 4, right parenthesis, squared, plus, 180 How many seconds after being launched will the object hit the ground?

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

my answer is$ 12

step-by-step explanation:

because 15 -2=12