5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence interval of the true mean weight.

( 8.11 , 9.69)

the 95% confidence interval of the true mean weight

= ( 8.11 , 9.69)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.9

Standard deviation r = 0.9

Number of samples n = 5

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

8.9+/-1.96(0.9/√5)

8.9+/-1.96(0.4025)

8.9+/- 0.79

= ( 8.11 , 9.69)

Therefore at 95% confidence interval (a,b) = ( 8.11 , 9.69)

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms