Is (1,2) the solution to the following system of equations? Show your work that proves whether it is or is not the solution.

no

Step-by-step explanation:

To determine if the given point is a solution.

Substitute the values x = 1, y = 2 into the left side of both equations and if equal to the right side then it is a solution.

Must be true for both equations

x - 3y = 1 - 3(2) = 1 - 6 = - 5 ≠ 7

4x + 2y = 4(1) + 2(2) = 4 + 4 = 8 ≠ 14

Thus (1, 2) is not a solution to the system of equations.

No (1,2) is not the solution but (4,-1) is the solution.

Step-by-step explanation:

solve by elimination

-4 (x - 3y)= 7(-4)   multiply this equation by  -4 to eliminate the x term

4x + 2y =4

New equation   -4x + 12y=-28

                           4x + 2y =-1 4  

                             14y= -14

                           divide both sides by 14

                   y= -1  

Plot the y solution into one of the equation to find x

   4x + 2(-1)=14

4x -2 = 14

      +2   +2

4x=16

x=4

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

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step-by-step explanation: