Consider the function. f(x) = x2 + 3 Which answer pairs a possible domain restriction for f(x) and its corresponding impact on f–1(x)? f(x) domain: x ≥ 3 f–1(x) domain: x ≥ 3 f(x) domain: x ≥ 3 f–1(x) range: x ≥ 3 f(x) domain: x ≥ 0 f–1(x) domain: x ≥ 0 f(x) domain: x ≥ 0 f–1(x) range: x ≥ 0

answer: give more info

step-by-step explanation:

what is the answer to this

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen