The perimeter of a rhombus is 52 cm. The length of one diagonal of the rumpus is 24 cm. What is the length of the other diagonal?

The perimeter of a rhombus is 52 cm.

=> length of side: L = 52/4 = 13 cm

Applying Pythagorean theorem for a particular right triangle inside rhombus, we have:

diagonal_2 = 2 x sqrt(side^2 - (diagonal_1/2)^2)

                   = 2 x sqrt(13^2 - (24/2)^2)

                   = 2 x 5 = 10 (cm)

=> Solution : 10 cm

Hope this helps!

:)

10 cm

Step-by-step explanation:

Each side = 52/2 = 13

Angle 1: X

24² = 13² + 13² - 2(13)(13)cosX

X = 134.7602701

Angle 2: 180 - X = 45.2397299

Diagonal² = 13² + 13² - 2(13)(13)cos(180-X)

Diagonal² = 100

Diagonal = 10

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

source

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest