Jerome is making prizes for a game at the school fair. he has two bags of different pins, one with 15 square pins and one with 20 round pins. every prize will have one kind of pin. each prize will have the same number of pins. what is the greatest number of pins jerome can put in each prize?

There are 5 pins which is the greatest number of pins that he can put in each prize.

Step-by-step explanation:

Since we have given that

Number of square pins = 15

Number of round pins = 20

We need to find the greatest number of pins Jerome can put in each prize.

According to question, Every prize will have one kind of pin. Each prize will have the same number of pins.

So, H.C.F. of 15 and 20 = 5

Hence, there are 5 pins which is the greatest number of pins that he can put in each prize.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.