What is the solution to the system of equations below? y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6 no solution infinitely many solutions (–16, 6) (–16, –2)

no solution

Step-by-step explanation:

Suppose the system equations are:

y = (-1/4)x + 2   (1)

3y = (-3/4)x – 6    (2)

If we multiply equation (1) by 3:

3y = (-3/4)x + 6      (1)

3y = (-3/4)x – 6       (2)

then subtract it from equation (2):

0y = 0x – 12

0 = -12

This is not possible, therefore, the system equation has no solution