Elena wants to build a one-sample z interval to estimate what proportion of computers produced at a

factory have a certain defect. She chooses a confidence level of 94%. A random sample of 200 computers

shows that 12 computers have the defect

What critical value z' should Elena use to construct this confidence interval?

The critical z-value elena should use to construct the given confidence interval is; 1.88

We are given;

Formula for confidence intervals of proportion is;

CI = p^ ± z√(p^(1 - p^)/n)

Since we are given Confidence level of 94%, the significance level is;

α = 100% - 94%

α = 0.06

The the z-score will be at the p-value of 1 - α/2

P-value = 1 - (0.06/2) = 0.97

From online p-value from z-score calculator, we have; z-score = 1.88

Read more about confidence intervals at; link

Z = 1.88

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

94% confidence level

So , z is the value of Z that has a pvalue of , so .

mxb67

step-by-step explanation: