The mean weight of four members of the wrestling team is 160 pounds. If three of them have weights of 125, 183, and 169 pounds, then what does the fourth wrestler weigh? 159 pounds 160 pounds 163 pounds 166 pounds

The mean weight of four members of the wrestling team is 160 pounds.

Three of them have weights of 125, 183, and 169 pounds, the remaining one has weight a.

=> (a + 125 + 183 + 169)/4 = 160

=> a = 160 x 4 - 125 -183 - 169 = 163

=> Option C (163 pounds) is correct.

Hope this helps!

:)

163

Step-by-step explanation:

Sum = mean × n

125 + 183 + 169 + X = 160 × 4

477 + X = 640

X = 640 - 477

X = 163

2x^2+5x+17

your welcome. : )

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)