Question
It takes Jan twice as many hours to walk 6 miles as it takes Bev to walk 4 miles. What is the ratio of Jan's
average walking rate to Bev's average walking rate?

the ratio of Jan's average walking rate to Bev's average walking rate is 3/4 or 3 : 4

Step-by-step explanation:

Let x and y represent jan and Bev's average walk rate.

Also t represent the time taken for Bev to walk 4 miles, so it will take jan 2t time to walk 6 miles

Given that;

It takes Jan twice as many hours to walk 6 miles as it takes Bev to walk 4 miles

For Bev;

y = 4/t

For Jan;

x = 6/(2t) = 3/t

the ratio of Jan's average walking rate to Bev's average walking rate is;

x/y = (3/t)/(4/t) = 3/4

the ratio of Jan's average walking rate to Bev's average walking rate is 3/4 or 3 : 4

69.64%

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: