Which congruence theorem can be used to prove △ABC ≅ △DEC? HL ASA SSS SAS

SAS Congruence Postulate

Step-by-step explanation:

In ΔABC and ΔDCE

AC=CE [given]→Side

∠ACB=∠DCE [vertically opposite angles]→Angle

BC=DC [given]→Side

∴ ΔABC ≅ ΔDCE [SAS congruence postulate]

SAS congruence postulate tells that if two sides and the included angle of one triangle are congruent to two sides and the included angle of other triangle, then the two triangles are congruent.

This is SAS.  Notice you have 2 sides that are equal to each other and the vertical angle between them.  Since the angle is between the 2 sides then the postulate that works is SAS.

step-by-step explanation:

this is a very good question

step-by-step explanation:

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