Given

\qquad m \angle AOCm∠AOCm, angle, A, O, C is a straight angle.

\qquad m \angle BOC = 6x + 29^\circm∠BOC=6x+29

∘

m, angle, B, O, C, equals, 6, x, plus, 29, degrees

\qquad m \angle AOB = 3x + 124^\circm∠AOB=3x+124

∘

m, angle, A, O, B, equals, 3, x, plus, 124, degrees

Find m\angle BOCm∠BOCm, angle, B, O, C:

m/angle BOC=47 degrees!!!

Step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.