A car dealership is expecting a shipment of cars and trucks valued at $460,000. Each car will have a list price of $18,500 and each truck will have a list price of $17,000. A total of 26 cars and trucks will be shipped.

Which pair of equations can be used to find the number of cars (x) and the number of trucks (y) in the shipment?

x+y = 26  

18500x+17,000y = 460,000

Step-by-step explanation:

number of cars is denoted by x

number of trucks is denoted by y

According to question

Total no. of cars and truck shipped = 26  1

Total no of cars shipped in terms of x and y = x+y  2

since equation 1 and 2 are representing the same thing , equating them together we have

x+y = 26  first equation

list price of car = $18500

if there are x cars then total price of car = x*price of one car

= $18500*x = $18500x

list price of truck = $17,000

if there are y trucks then total price of trucks = y*price of one truck

= $17,000*y = $17,000y  

Given that

Total value of shipment of cars and truck = $460,000   3

Total value of cars shipped in terms of x and y = $18500x+$17,0004

since equation 3 and 4 are representing the same thing , equating them together we have

$18500x+$17,000y = $460,000  second equation

Removing $ sign to standardize the equation

18500x+17,000y = 460,000

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

x + 4/7

step-by-step explanation:

use cymath