A discount airline sells a certain number of tickets, x, for a flight for $90 each. It sells the number of remaining tickets, y, for $250 each. For a particular flight, the airline sold 120 tickets and collected a total of $27,600 from the sale of those tickets. Which system of equations represents this relationship between x and y?

x+y= 120

90x+250y=27,600

Step-by-step explanation:

x= number of certain tickets

y= number of remaining tickets

The statement indicates that for a particular flight the airline sold 120 tickets which means that the sum of the different tickets is 120. The first equation is:

x+y= 120

Then, the statement says that certain number of tickets costs $90 and the remaining tickets cost $250 and that for a particular flight, the airline collected $27,600. From this, you can say that the number of certain tickets, x, multiply for its price that is $90 plus the number of the remaining tickets, y, multiply for its price that is $250 would be equal to $27,600. The equation would be:

90x+250y=27,600

According to this, the answer is that the system of equations that represents this relationship between x and y is:

x+y= 120

90x+250y=27,600

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17