Write an equation of the line that passes through the point (5,-4) and has a slope of 2.

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x - 14

Step-by-step explanation:

Point slope formula: (y + 4) = 2(x - 5)

Slope intercept formula: y = 2x + b, -4 = 10 + b, b = -14

y = 2x - 14

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step-by-step explanation:

the x's and the y's both go up the same amount each time, therefore it will be a linear function because it will go in a straight line when drawn on a graph.

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< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐