A sandwich shop loses $1.20 every time somebody buys a sandwich, but makes $1.80 every time somebody buys a drink. One day, the shop sells 100 drinks. Which inequality can you use to find possible numbers of sandwiches that it could sell and still make a profit of more than $100? A:1.2x – 100(1.8) > 100 B:100(1.2) + 1.8x > 100 C:100(1.2) – 1.8x > 100 D:100(1.8) – 1.2x > 100

A, B, and C

I think. Please let me know if wrong.

Heres what i did:

1.8 x 100 = 180.

180 - 80 = 100

(they made over 100 in profit)

A. 1.2 x 0 = 0

B. 1.2 x 40 - 48

C. 1.2 x 60 = 72

D. 1.2 x 70 = 84

E. 1.2 x 80 =96

D and E bot Exceed 80 so it has to be AB and C

Hope this Helps ☺

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

25/6

step-by-step explanation:

you multiply 4 by the denominator (4*6=24) and add it to the numerator which makes it 25/6.