If the radius and the height of a right cylinder are both tripled, by what factor will the surface area increase?

Answer :

The surface area will increase by 9

Step-by-step explanation :

This problem bothers on the mensuration of solid shapes, a cylinder

Step one

We know that the surface area of a cylinder is given as

A= 2πrh + 2πr²

A= 2π(rh + r²)

Since the radius and the height is tripled r=3r, h= 3h

A= 2π(3r*3h + (3r)²)

A= 2π(9rh + 9r²)

Factoring 9 out we have

A= 9*2π(rh + r²)

Hence the surface area will increase by 9

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.